1/4(b-8)^2=7

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Solution for 1/4(b-8)^2=7 equation: 


b in (-oo:+oo)

(1/4)*(b-8)^2 = 7 // - 7

(1/4)*(b-8)^2-7 = 0

1/4*(b-8)^2-7 = 0

1/4*(b-8)^2-7 = 0

1/4*b^2-4*b+9 = 0

1/4*b^2-4*b+9 = 0

1/4*b^2-4*b+9 = 0

DELTA = (-4)^2-(1/4*4*9)

DELTA = 7

DELTA > 0

b = (7^(1/2)+4)/(1/4*2) or b = (4-7^(1/2))/(1/4*2)

b = 2*(7^(1/2)+4) or b = 2*(4-7^(1/2))

(b-2*(4-7^(1/2)))*(b-2*(7^(1/2)+4)) = 0

(b-2*(4-7^(1/2)))*(b-2*(7^(1/2)+4)) = 0

( b-2*(4-7^(1/2)) )

b-2*(4-7^(1/2)) = 0 // + -2*(4-7^(1/2))

b = -(-2*(4-7^(1/2)))

b = 2*(4-7^(1/2))

( b-2*(7^(1/2)+4) )

b-2*(7^(1/2)+4) = 0 // + -2*(7^(1/2)+4)

b = -(-2*(7^(1/2)+4))

b = 2*(7^(1/2)+4)

b in { 2*(4-7^(1/2)), 2*(7^(1/2)+4) }

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